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The low pass filter only allows low frequency signals from 0Hz to its cut-off frequency, ƒc point to pass while blocking those any higher.



Image Added



fc = 1/(2πRC)

So, if

...


fc = 1000 Hz


R=470

C=1/(2πRFc) = 1/(2π*1000*470) =  0.39 μF


R=1K

C=1/(2πRFc) = 1/(2π*1000*1000) = 0.159 μF


R=10k

C=1/(2πRFc) = 1/(

...

*10000*1000) = 15.9 nF

...


R=47K

C=1/(2πRFc) = 1/(2π*1000*47000) =  3.39 nFImage Removed